In this article, you will know the Weight of Material carried by Truck. The Material Shall is Aggregate and Fine Aggregate (Sand) that is fulfilling in the Dumper Truck. For the Calculation the Length of the Dumper truck is 16′, the Breadth is 8′-3″ and the Height is taken at three Different Locations i.e. 3’6″, 3′-8″, 3′-9″.

**Let’s First Fill the Aggregate in Dumper.**

**Weight of Aggregate Carried by the Dumper Truck**

**Given Data**

Length (L) = 16′.

Breadth (B) = 8′-3″.

Height (H) is taken at three location = 3′-6″, 3′-8″, 3′-9″.

**Bulk Density of Aggregate = 1750 Kg/m ^{3}.**

Average height (H) = 3′-6″, 3′-8″, 3′-9″ = (3.5’+3.67’+3.75′)/3 = 3.64′.

Now Find the Volume of Aggregate (V) = L X B X H = 16′ x 8.25′ x 3.64′ = **480.48 CFT.**

AS the Bulk Density of Aggregate is in Cubic meter so we have to convert the Volume of Aggregate in Cubic meter.

As we Know that, 1 m^{3} =35.314 CFT. Then Volume of Aggregate = 480.48 /35.314 = 13.605 m^{3}.

Weight of Aggregate Carried by the Dumper Truck = Total Volume of Aggregate x Bulk Density of Aggregate.

Weight of Aggregate Carried by the Dumper Truck = 13.605 m^{3} x 1750 Kg/m^{3} = **23,808.75 kg = 23.9 MT.**

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**Weight of sand Carried by the Dumper Truck**

Length (L) = 16′.

Breadth (B) = 8′-3″.

Height (H) is taken at three location = 3′-6″, 3′-8″, 3′-9″.

Bulk Density of sand = 1750 Kg/m^{3}.

**Note: – Bulk Density of Sand Ranges from 1520-1680 Kg/m ^{3}.**

Average height (H) = 3′-6″, 3′-8″, 3′-9″ = (3.5’+3.67’+3.75′)/3 = 3.64′.

Now Find the Volume of Aggregate (V) = L X B X H = 16′ x 8.25′ x 3.64′ = **480.48 CFT.**

AS the Bulk Density of sand is in Cubic meter so we have to convert the Volume of sand in Cubic meter.

As we Know that, 1 m^{3} =35.314 CFT. Then Volume of sand = 480.48 /35.314 = 13.605 m^{3}.

Weight of Aggregate Carried by the Dumper Truck = Total Volume of sand x Bulk Density of sand.

= 13.605 m^{3} x 1600 Kg/m^{3} = **21,768 kg = 21.768 MT.**

**Weight of Aggregate Carried by the Tractor trolley**

The available size of Tractor Trolley in the market are 10′ x 6′ x 1.25′, 10′ x 6′ x 1.5′, 10′ x 6′ x 2′, 10′ x 5′ x 2′ etc. The Size of Trolley considered for the calculation of Weight of Aggregate Carried by the Tractor trolley is 10′ x 6′ x 2′.

**Given Data**

Length of the Tractor trolley (L) = 10′.

Breadth of the Tractor trolley (B) = 6′.

Height of Tractor trolley (H) = 2′

Bulk Density of Aggregate = 1750 Kg/m^{3}.

Now Find the Volume of Aggregate (V) = L X B X H = 10′ x 6′ x 2′. = **120 CFT.**

AS the Bulk Density of Aggregate is in Cubic meter so we have to convert the Volume of Aggregate in Cubic meter.

As we Know that, 1 m^{3} = 35.314 CFT. Then Volume of Aggregate = 120 /35.314 = 3.398 m^{3}.

Weight of Aggregate Carried by the Tractor trolley = Total Volume of Aggregate x Bulk Density of Aggregate.

= 3.398 m^{3} x 1750 Kg/m^{3} = **5,946.5 kg = 5.9465 MT.**

**Weight of sand Carried by the Tractor trolley**

The Size of the Trolley considered for the calculation of the Weight of sand Carried by the Tractor trolley is 10′ x 5′ x 2′.

**Given Data**

Length of the Tractor trolley (L) = 10′.

Breadth of the Tractor trolley (B) = 5′.

Height of Tractor trolley (H) = 2′.

Bulk Density of sand = 1600 Kg/m^{3}.

Now Find the Volume of sand (V) = L X B X H = 10′ x 5′ x 2′ = **100 CFT.**

AS the Bulk Density of sand is in Cubic meter so we have to convert the Volume of sand in Cubic meter.

As we Know that, 1 m^{3} = 35.314 CFT. Then Volume of sand = 100 /35.314 = 2.831 m^{3}.

Weight of sand Carried by the Tractor trolley = Total Volume of sand x Bulk Density of sand.

= 2.831 m^{3} x 1600 Kg/m^{3} = **4,529.6 kg = 4.5296 MT.**