### Objective Questions And Answers for All Competitive Exams (Loksewa Sub Engineer, Overseer, Sub Overseer, Central, and Pardesh Level).

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**The flexural tensile strength of M15 grade of Concrete is**

a. 2.5

b. 2.71

c. 3

d. 2.9

**2. Which code is used for Mild Steel**

a. IS 432

b. IS 383

c. IS 1786

d. IS 456-200

**3. The slump of pump concrete should be from…?**

a. 50 mm-100 mm

b. 0 mm-25 mm

c. 100 mm-150 mm

d. non of these.

**4. What is the Maximum cement content (KG/m ^{3} )for Reinforced Concrete Structure As per IS 456-2000?**

a. 300

b. 360

c. 460

d. 450

**5. What is Factor of Safety of Concrete subjected under direct compression?**

a. 1.5

b. 3

c. 4

d. 1.15

**6. What is the Maximum size of Aggregate that can be used in case of No flow restriction?**

a. 20 mm.

b. 40 mm.

c. 25 mm.

d. 35 mm.

**7. Creep Occurs due**

a. Live Load.

b. Dead Load.

c. Earthquake load.

d. Permanent Attached load.

e. Both (b) and (d)

**8. Modulus of Elasticity of Concrete increase with**

a. Decrease in grade of Concrete.

b. Increase in Grade of Concrete.

c. Increase in Grade of Steel.

d. Decrease in Grade of Steel.

**9. What is the value of Poisson’s ratio of steel in elastic state?**

a. 0.4

b. 0.3

c. 0.25

d. 0.2.9

**10. In Limit State Method, Design Load is equal to**

a. Partial Safety factor x Design load.

b. Partial Safety factor x working load.

c. Partial Safety factor x load.

d. Partial Safety factor x Characteristics Load.

## Objective Questions And Answers for All Competitive Exams

### Answers

1 b) 2.71

Explanation:

- The flexural tensile strength of concrete (fcr) = 0.7Ѵfck
- For M15 grade of Concrete, fcr = 0.7Ѵ15 =2.711.
- The Split tensile strength of Concrete = 0.462 Ѵfck.
- The Direct tensile strength of Concrete = 0.35 Ѵfck.

2 Ans a) IS 432

Explanation:

IS 432: Mild Steel.

IS 1786: High Yield Strength Deformed Bars (HYSD).

Indian Standard (IS 383) for Aggregate.

IS: 456-2000: For Reinforced Concrete Structure.

3: c) 100 mm-150 mm

4 d). 450 Kg/ m^{3}

Explanation:

S.No | Exposure Condition | Minimum Grade of Concrete (RCC) | Minimum Cement Content (Kg/m^{3}) |

1 | Mild | M 20 | 300 |

2 | Moderate | M 25 | 300 |

3 | Severe | M 30 | 320 |

4 | Very Severe | M 35 | 340 |

5 | Extreme | M 40 | 360 |

5 c). 4

Explanation:

In Working Stress Method (WSM)

- F.O.S of Concrete Subjected under Bending Compression = 3.
- Factor of safety of Concrete Subjected under Direct Compression = 4.
- F.O.S of Steel =1.8

In Limit State Method (LSM)

- Partial Safety Factor of Concrete =1.5
- Partial Safety Factor of Steel =1.15

6 Ans: b)

Explanation:

- Generally the nominal size of aggregate used up to 20 mm.
- Maximum size of aggregate in case of No flow restriction is 40 mm.
- Maximum size of Aggregate shall not be more than 1/4 th of the thickness of Member.

7 Ans: e)

Explanation:

- Creep means at constant stress, continuously increase in strain is called creep.
- It is Time dependent phenomenon.
- It occurs due to dead load and Permanent attached load.
- Creep Coefficient (Ө) = Ultimate Creep Strain / Elastic strain.

8 Ans: b)

Explanation:

- Modulus of concrete (Ec) = 5000*Ѵfck (As per IS 456-2000), so Ec α fck.
- Modulus of concrete (Ec) = 5700*Ѵfck, (As per IS 456-1987) so Ec α fck.

9 Ans: b)

Explanation:

- Poisson’s ratio of steel in elastic state = 0.3
- Poisson’s ratio of steel in plastic state = 0.5

10 Ans: c)

Explanation:

- In the case of LSM, Design Load = Partial Safety Factor x Characteristics Load.
- In the Case of WSM, Working Load = Characteristics Load.