In this article, we will learn to calculate the number of AAC Blocks, Cement, sand required for an Autoclaved Aerated Concrete (AAC ) Block Wall having 7 m Long, 3.2 m Height, and 0.15 Width. The block wall has a mortar joint of the cement-sand ratio of 1:4. The AAC block of Size 625 mm x 240 mm x 150 mm.

### How to Calculate the Number of Autoclaved Aerated Concrete (AAC) Blocks, Cement sand Required for Block work?

Let’s First Calculate for 1 cum Blockwork.

Volume of Block work = 1 cum.

Size of Bricks = 625 mm x 240 mm x 150 mm.

Volume of One AAC Block without mortar = 0.625 m x 0.24 m x 0.15 m = 0.0225 cum.

Number of AAC Block Required without Mortar = (Volume of Block Work)/ (Volume of AAC Block without Mortar)

= 1/ (0.0225) **= 44.44 Nos.**

Add 5 mm thickness mortar joint, Hence

Size of AAC Block = 630 mm x 245 mm x 155 mm.

Volume of AAC Block with mortar = 0.63 m x 0.245 m x 0.155 m = 0.0239 cum

Number of AAC Blocks Required with Mortar = (Volume of lock Work)/ (Volume of AAC Block with Mortar)

= 1/ (0.0239) **= 42 Nos.**

Hence, the numbers of Blocks have reduced from 44 to 42 due to the presence of Mortar.

Quantity of Mortar Volume = Volume of Blockwork – (Volume of AAC Block without mortar x Number of AAC Block required with mortar)

= 1 – (0.0225 x 42) = **0.055 cum.**

Therefore we need 42 Bricks and 0.055 cum Cement Mortar for 1 Cum Blockwork.

Now we also have to find how much cement and how much quantity of sand is needed for 0.055 cum of Mortar.

Wet volume of Cement Mortar = 0.055 cum.

Dry Volume of Mortar = 0.055 x 1.33 = 0.07315 cum.

C: S Ratio = 1:4

#### Cement Calculation

Cement in Cum = (Volume of Mortar x Ratio of Cement) / (Sum of Ratio)

= (0.07315 x 1) (1+4) = 0.07315/5 = **0.01463 m ^{3}**

Cement in Kilogram = 0.01463 x 1440 = **21.0672 Kg.**

Cement in Bag = 21.0672 / 50 = **0.43 Bags.**

#### Sand Calculation

Sand in cum = (Volume of Mortar x Ratio of sand) / (Sum of Ratio)

= (0.07315 x 6) /(1+4) = 0.4389/5 = **0.08778 m ^{3}**

In Short for 1 Cum Brickwork we need,

**Bricks = 42 Nos.**

**Cement = 0.43 Bags**

**Sand = 0.08778 cum.**

Now Consumption of Material for brick wall of Size 7 m Long, 3.2 m Height and 0.15 Width

Volume of Brick wall = 7 x 3.2 x 0.15 = 3.36 cum.

Therefore, the consumption of Material shall be such that;

Cement = 0.43 Bags x 3.36 = **1.45 Bags.**

Sand = 0.08778 cum x 3.36 = **0.3 cum.**

Bricks = 42 Bricks x 3.36 = **142 Nos.**

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